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The Number of Consecutive Heads in a Run Hirose, Hideo ヒロセ, ヒデオ 廣瀬, 英雄 publisher coin tossing run consecutive heads solitary head coin dual problem application/pdf How many consecutive heads do we observe in a run of coin tossing of length n? Although the problem seems to be easy to answer, this would be actually a little bit tough when we try to prove it straightforwardly. The expected number of consecutive heads in a run is 3n-2/8 (n≧2) using the recursive formula.|However, if we define a solitary head coin such that a head coin is isolated by neighboring tail coin(s) in a run, the problem of how many solitary heads we observe in a run can be solved easily. The expected number of solitary heads in a run is n+2/8 (n≧2). Since the problem of solitary head coin becomes a dual problem of the above, the consequence of the problem of the consecutive heads is derived easily by considering the probability of a solitary coin appearance. 広島工業大学 2019-02 eng departmental bulletin paper VoR https://it-hiroshima.repo.nii.ac.jp/records/1086 AA11599110 13469975 広島工業大学紀要. 研究編 53 177 179 https://it-hiroshima.repo.nii.ac.jp/record/1086/files/research53_177-179.pdf application/pdf 533.8 kB 2023-03-30